Optimal. Leaf size=275 \[ -\frac{b \text{PolyLog}\left (2,-e^{2 \sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^3}+\frac{b \text{PolyLog}\left (2,e^{2 \sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^3}+\frac{b^2 \text{PolyLog}\left (3,-e^{2 \sinh ^{-1}(c x)}\right )}{2 d^3}-\frac{b^2 \text{PolyLog}\left (3,e^{2 \sinh ^{-1}(c x)}\right )}{2 d^3}-\frac{4 b c x \left (a+b \sinh ^{-1}(c x)\right )}{3 d^3 \sqrt{c^2 x^2+1}}-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (c^2 x^2+1\right )^{3/2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (c^2 x^2+1\right )}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (c^2 x^2+1\right )^2}-\frac{2 \tanh ^{-1}\left (e^{2 \sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )^2}{d^3}-\frac{b^2}{12 d^3 \left (c^2 x^2+1\right )}+\frac{2 b^2 \log \left (c^2 x^2+1\right )}{3 d^3} \]
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Rubi [A] time = 0.506935, antiderivative size = 275, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 11, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.423, Rules used = {5755, 5720, 5461, 4182, 2531, 2282, 6589, 5687, 260, 5690, 261} \[ -\frac{b \text{PolyLog}\left (2,-e^{2 \sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^3}+\frac{b \text{PolyLog}\left (2,e^{2 \sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^3}+\frac{b^2 \text{PolyLog}\left (3,-e^{2 \sinh ^{-1}(c x)}\right )}{2 d^3}-\frac{b^2 \text{PolyLog}\left (3,e^{2 \sinh ^{-1}(c x)}\right )}{2 d^3}-\frac{4 b c x \left (a+b \sinh ^{-1}(c x)\right )}{3 d^3 \sqrt{c^2 x^2+1}}-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (c^2 x^2+1\right )^{3/2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (c^2 x^2+1\right )}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (c^2 x^2+1\right )^2}-\frac{2 \tanh ^{-1}\left (e^{2 \sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )^2}{d^3}-\frac{b^2}{12 d^3 \left (c^2 x^2+1\right )}+\frac{2 b^2 \log \left (c^2 x^2+1\right )}{3 d^3} \]
Antiderivative was successfully verified.
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Rule 5755
Rule 5720
Rule 5461
Rule 4182
Rule 2531
Rule 2282
Rule 6589
Rule 5687
Rule 260
Rule 5690
Rule 261
Rubi steps
\begin{align*} \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{x \left (d+c^2 d x^2\right )^3} \, dx &=\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (1+c^2 x^2\right )^2}-\frac{(b c) \int \frac{a+b \sinh ^{-1}(c x)}{\left (1+c^2 x^2\right )^{5/2}} \, dx}{2 d^3}+\frac{\int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{x \left (d+c^2 d x^2\right )^2} \, dx}{d}\\ &=-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (1+c^2 x^2\right )^{3/2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (1+c^2 x^2\right )}-\frac{(b c) \int \frac{a+b \sinh ^{-1}(c x)}{\left (1+c^2 x^2\right )^{3/2}} \, dx}{3 d^3}-\frac{(b c) \int \frac{a+b \sinh ^{-1}(c x)}{\left (1+c^2 x^2\right )^{3/2}} \, dx}{d^3}+\frac{\left (b^2 c^2\right ) \int \frac{x}{\left (1+c^2 x^2\right )^2} \, dx}{6 d^3}+\frac{\int \frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{x \left (d+c^2 d x^2\right )} \, dx}{d^2}\\ &=-\frac{b^2}{12 d^3 \left (1+c^2 x^2\right )}-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (1+c^2 x^2\right )^{3/2}}-\frac{4 b c x \left (a+b \sinh ^{-1}(c x)\right )}{3 d^3 \sqrt{1+c^2 x^2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (1+c^2 x^2\right )}+\frac{\operatorname{Subst}\left (\int (a+b x)^2 \text{csch}(x) \text{sech}(x) \, dx,x,\sinh ^{-1}(c x)\right )}{d^3}+\frac{\left (b^2 c^2\right ) \int \frac{x}{1+c^2 x^2} \, dx}{3 d^3}+\frac{\left (b^2 c^2\right ) \int \frac{x}{1+c^2 x^2} \, dx}{d^3}\\ &=-\frac{b^2}{12 d^3 \left (1+c^2 x^2\right )}-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (1+c^2 x^2\right )^{3/2}}-\frac{4 b c x \left (a+b \sinh ^{-1}(c x)\right )}{3 d^3 \sqrt{1+c^2 x^2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (1+c^2 x^2\right )}+\frac{2 b^2 \log \left (1+c^2 x^2\right )}{3 d^3}+\frac{2 \operatorname{Subst}\left (\int (a+b x)^2 \text{csch}(2 x) \, dx,x,\sinh ^{-1}(c x)\right )}{d^3}\\ &=-\frac{b^2}{12 d^3 \left (1+c^2 x^2\right )}-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (1+c^2 x^2\right )^{3/2}}-\frac{4 b c x \left (a+b \sinh ^{-1}(c x)\right )}{3 d^3 \sqrt{1+c^2 x^2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (1+c^2 x^2\right )}-\frac{2 \left (a+b \sinh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{2 b^2 \log \left (1+c^2 x^2\right )}{3 d^3}-\frac{(2 b) \operatorname{Subst}\left (\int (a+b x) \log \left (1-e^{2 x}\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^3}+\frac{(2 b) \operatorname{Subst}\left (\int (a+b x) \log \left (1+e^{2 x}\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^3}\\ &=-\frac{b^2}{12 d^3 \left (1+c^2 x^2\right )}-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (1+c^2 x^2\right )^{3/2}}-\frac{4 b c x \left (a+b \sinh ^{-1}(c x)\right )}{3 d^3 \sqrt{1+c^2 x^2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (1+c^2 x^2\right )}-\frac{2 \left (a+b \sinh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{2 b^2 \log \left (1+c^2 x^2\right )}{3 d^3}-\frac{b \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (-e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{b \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{b^2 \operatorname{Subst}\left (\int \text{Li}_2\left (-e^{2 x}\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^3}-\frac{b^2 \operatorname{Subst}\left (\int \text{Li}_2\left (e^{2 x}\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{d^3}\\ &=-\frac{b^2}{12 d^3 \left (1+c^2 x^2\right )}-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (1+c^2 x^2\right )^{3/2}}-\frac{4 b c x \left (a+b \sinh ^{-1}(c x)\right )}{3 d^3 \sqrt{1+c^2 x^2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (1+c^2 x^2\right )}-\frac{2 \left (a+b \sinh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{2 b^2 \log \left (1+c^2 x^2\right )}{3 d^3}-\frac{b \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (-e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{b \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{b^2 \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{2 \sinh ^{-1}(c x)}\right )}{2 d^3}-\frac{b^2 \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{2 \sinh ^{-1}(c x)}\right )}{2 d^3}\\ &=-\frac{b^2}{12 d^3 \left (1+c^2 x^2\right )}-\frac{b c x \left (a+b \sinh ^{-1}(c x)\right )}{6 d^3 \left (1+c^2 x^2\right )^{3/2}}-\frac{4 b c x \left (a+b \sinh ^{-1}(c x)\right )}{3 d^3 \sqrt{1+c^2 x^2}}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{4 d^3 \left (1+c^2 x^2\right )^2}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^2}{2 d^3 \left (1+c^2 x^2\right )}-\frac{2 \left (a+b \sinh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{2 b^2 \log \left (1+c^2 x^2\right )}{3 d^3}-\frac{b \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (-e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{b \left (a+b \sinh ^{-1}(c x)\right ) \text{Li}_2\left (e^{2 \sinh ^{-1}(c x)}\right )}{d^3}+\frac{b^2 \text{Li}_3\left (-e^{2 \sinh ^{-1}(c x)}\right )}{2 d^3}-\frac{b^2 \text{Li}_3\left (e^{2 \sinh ^{-1}(c x)}\right )}{2 d^3}\\ \end{align*}
Mathematica [C] time = 3.67633, size = 560, normalized size = 2.04 \[ \frac{a b \left (24 \text{PolyLog}\left (2,e^{2 \sinh ^{-1}(c x)}\right )+12 \left (\sinh ^{-1}(c x) \left (\sinh ^{-1}(c x)-4 \log \left (1+i e^{\sinh ^{-1}(c x)}\right )\right )-4 \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right )\right )+12 \left (\sinh ^{-1}(c x) \left (\sinh ^{-1}(c x)-4 \log \left (1-i e^{\sinh ^{-1}(c x)}\right )\right )-4 \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right )\right )-\frac{15 \left (\sqrt{c^2 x^2+1}-i \sinh ^{-1}(c x)\right )}{c x+i}-\frac{15 \left (\sqrt{c^2 x^2+1}+i \sinh ^{-1}(c x)\right )}{c x-i}-\frac{3 \sinh ^{-1}(c x)+\sqrt{c^2 x^2+1} (c x-2 i)}{(c x-i)^2}-\frac{3 \sinh ^{-1}(c x)+\sqrt{c^2 x^2+1} (c x+2 i)}{(c x+i)^2}-24 \sinh ^{-1}(c x)^2+48 \sinh ^{-1}(c x) \log \left (1-e^{2 \sinh ^{-1}(c x)}\right )\right )+b^2 \left (24 \sinh ^{-1}(c x) \text{PolyLog}\left (2,-e^{-2 \sinh ^{-1}(c x)}\right )+24 \sinh ^{-1}(c x) \text{PolyLog}\left (2,e^{2 \sinh ^{-1}(c x)}\right )+12 \text{PolyLog}\left (3,-e^{-2 \sinh ^{-1}(c x)}\right )-12 \text{PolyLog}\left (3,e^{2 \sinh ^{-1}(c x)}\right )-\frac{2}{c^2 x^2+1}+16 \log \left (c^2 x^2+1\right )+\frac{12 \sinh ^{-1}(c x)^2}{c^2 x^2+1}+\frac{6 \sinh ^{-1}(c x)^2}{\left (c^2 x^2+1\right )^2}-\frac{32 c x \sinh ^{-1}(c x)}{\sqrt{c^2 x^2+1}}-\frac{4 c x \sinh ^{-1}(c x)}{\left (c^2 x^2+1\right )^{3/2}}-16 \sinh ^{-1}(c x)^3-24 \sinh ^{-1}(c x)^2 \log \left (e^{-2 \sinh ^{-1}(c x)}+1\right )+24 \sinh ^{-1}(c x)^2 \log \left (1-e^{2 \sinh ^{-1}(c x)}\right )+i \pi ^3\right )+\frac{12 a^2}{c^2 x^2+1}+\frac{6 a^2}{\left (c^2 x^2+1\right )^2}-12 a^2 \log \left (c^2 x^2+1\right )+24 a^2 \log (c x)}{24 d^3} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.237, size = 1129, normalized size = 4.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{4} \, a^{2}{\left (\frac{2 \, c^{2} x^{2} + 3}{c^{4} d^{3} x^{4} + 2 \, c^{2} d^{3} x^{2} + d^{3}} - \frac{2 \, \log \left (c^{2} x^{2} + 1\right )}{d^{3}} + \frac{4 \, \log \left (x\right )}{d^{3}}\right )} + \int \frac{b^{2} \log \left (c x + \sqrt{c^{2} x^{2} + 1}\right )^{2}}{c^{6} d^{3} x^{7} + 3 \, c^{4} d^{3} x^{5} + 3 \, c^{2} d^{3} x^{3} + d^{3} x} + \frac{2 \, a b \log \left (c x + \sqrt{c^{2} x^{2} + 1}\right )}{c^{6} d^{3} x^{7} + 3 \, c^{4} d^{3} x^{5} + 3 \, c^{2} d^{3} x^{3} + d^{3} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{2} \operatorname{arsinh}\left (c x\right )^{2} + 2 \, a b \operatorname{arsinh}\left (c x\right ) + a^{2}}{c^{6} d^{3} x^{7} + 3 \, c^{4} d^{3} x^{5} + 3 \, c^{2} d^{3} x^{3} + d^{3} x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a^{2}}{c^{6} x^{7} + 3 c^{4} x^{5} + 3 c^{2} x^{3} + x}\, dx + \int \frac{b^{2} \operatorname{asinh}^{2}{\left (c x \right )}}{c^{6} x^{7} + 3 c^{4} x^{5} + 3 c^{2} x^{3} + x}\, dx + \int \frac{2 a b \operatorname{asinh}{\left (c x \right )}}{c^{6} x^{7} + 3 c^{4} x^{5} + 3 c^{2} x^{3} + x}\, dx}{d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{2}}{{\left (c^{2} d x^{2} + d\right )}^{3} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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